Hobbs Carroll
09/10/2023 · High School

Represent the given statements in the form of linear equations. (ii) दस स्थानको अङ्क पत्ता लगाउनुहोस् । (Find the digit at tenth place.) (iii) उत्त/ सड्ख्या पत्ता लगाउनुहोस् । (Find the number.) 2 अड्कको सङ्य्यामा अड्कहरूको योग 11 छ । उक्त सङ्ख्याको अड्कलाई स्थानमान परिवर्तन गर्दा बन्ने सङ्य्या सुरुको सह् ब्रा भन्दा 45 ले बढी हुन्छ भने, The sum of digits in a two digit number is 11 . The number formed by interchanging the digits of that number will be 45 more than the original number. (i) दिइएको कथनहरूलाई रेखीय समीकरणको रूपमा लेख्नुहोस् । Represent the given statements in the form of linear equations. (ii) द्रस स्थानको अङ्क पत्ता लगाउनुहोस् । (Find the digit at tenth place.) (iii) सुरको सङ्या पत्ता लगाउनुहोस् । (Find the original number.)

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Let the two-digit number be 10x + y, where x is the tens digit and y is the units digit. 1. Sum of digits: x + y = 11 2. Interchanged number: 10y + x = 10x + y + 45 Solving these equations: - From the first equation, y = 11 - x - Substitute into the second equation: 10(11 - x) + x = 10x + (11 - x) + 45 - Simplify: 110 - 10x + x = 10x + 11 - x + 45 - Combine like terms: 110 - 9x = 9x + 56 - Add 9x to both sides: 110 = 18x + 56 - Subtract 56: 54 = 18x - Divide by 18: x = 3 Then, y = 11 - 3 = 8 So, the original number is 38. The digit at the tenth place is 3. The number formed by interchanging the digits is 83, which is 45 more than 38. Therefore, the answers are: - Digit at tenth place: 3 - Original number: 38

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