Two systems of equations are given below. For each system, choose the best description of its solution. If applicable, give the solution. System \( A \) \( - 4 x - y = - 8 \) \( - 4 x + y = - 8\) The system has no solution. The system has a unique solution: \(( x , y ) = ( \square , \square ) \)The system has infinitely many solutions. They must satisfy the following equation: \(y = \square \) System B \( 2 x - y - 2 = 0 \) \( - 2 x + y = - 2\) The system has no solution. The system has a unique solution: \(( x , y ) = ( \square , \square ) \)The system has infinitely many solutions. They must satisfy the following equation: \( y = \square \) 

USING EQUATIONS to solve WORD PROBLEN Directions: Set up and solve an equation for each problem below. \( \begin{array}{l}\text { 2. Five less than twice a number is equal to one } \\ \text { half the difference of three times the number } \\ \text { and 13. Find the number. }\end{array} \)

USING EQUATIONS to solve WORD PROBLEMS Directions: Set up and solve an equation for each problem below. 1. The product of 7 and a number, increased by 3, is equal to twice the number, subtracted from 39. Find the number.

USING EQUATIONS to solve WORD PROBLEMS Directions: Set up and solve an equation for each problem below. 7. The measure of one angle is str more than half the measure of another angle. If the angles are complementary, find both measures.

USING EQUATIONS to solve WORD PROBLEMS Directions: Set up and solve an equation for each problem below. 8. Kelly, Laura, and Tia sold boxes of cookies fol fundraiser. Kelly sold 15 boxes less than Laura Tia sold twice as many boxes as Kelly. If they sold 83 boxes of cookies in total, how many boxes did each girl sell?

Two cubic roots are given below. \( \sqrt[3]{27} \) and \( \sqrt[3]{343} \) Write \( \mathrm{a} \times \mathrm{a} \times \mathrm{a} \times \mathrm{a} \times \mathrm{a} \times \mathrm{a} \) in the form of indices (b) Multiply the given two cubic roots. c) Prove that: \( \left(\frac{\mathrm{x}^{a}}{\mathrm{x}^{b}}\right)^{a+b}\left(\frac{x^{b}}{x^{c}}\right)^{b+c}\left(\frac{\mathrm{x}^{c}}{\mathrm{x}^{a}}\right)^{c+a}=1 \)