girl-logo

Ask Questions

Algebra Questions & Answers

Q:
1.2 Given: \( f(x)=k x^{2}-(k+2) x+k+2+\frac{1}{k}=0 \) where \( k \neq 0 \), determine: 1.2.1 the value(s) of \( k \) for which the function has non -Real roots. 1.2.2 for which value(s) of \( k \) will \( g(x)=\frac{1}{k} \) be a tangent to \( f \).
Q:
Let \( m=7 \) 7. \( \left(m^{2}-9\right) \div 2 \)
Q:
Use propenties of logarithms to condense the logarithmic expression. Write the expression as a single logarithm whose coefficient is 1 . Where possible, evaluate logarithmic expressions. \( \frac{1}{2} \log _{5} x+\log _{5} y \)
Q:
\( 2 ( \log _ { a } c + \log _ { b } c ) = 9 \log _ { a b } c \)
Q:
Condensing Logarithmic Expressions. Rewrite each of the following logarithmic expressions using a single logarithm. \( \begin{array}{ll}\text { 1. } \frac{1}{3} \log _{2} 6+\frac{1}{3} \log _{2} x+\frac{2}{3} \log _{2} y & \text { 3.) } 2 \ln (x+3)+\ln x-\ln (2 x-1)\end{array} \)
Q:
\( \left. \begin{array} { l } { \left. \begin{array} { l } { \frac { 2 x } { 2 } \leq - \frac { 8 } { 2 } } \\ { x \leq - 4 } \end{array} \right. \quad ( - \infty , - 4 ] \cup [ 6 , \infty ) } \\ { + 1 / 2 } \end{array} \right. \)
Q:
Simplify the following expressions: 1.2.1 \( \frac{5}{a}-\frac{5}{a^{2}-a} \) \( 1.2 .2 \frac{x-1}{\sqrt{x}+1} \)
Q:
Use propertius of logarithms to expand the logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. \[ \log _{3}\left(\frac{\sqrt{x}}{9}\right) \]
Q:
\( \frac { x } { 1,2 } = \frac { 5 } { 1 } \Rightarrow x = \)
Q:
Use properties of logarithms to expand the logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. \[ \log _{b}\left(y z^{4}\right) \]

Test your knowledge on Algebra!

Select the correct answer and check your answer

6 7 8 9 10 11 12 13 14 15
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text

Enter your question here…

By image
Re-Upload
Uploaded Files
xxxx.png0%
Submit
📸 STUDY CAN BE A REAL STRUGGLE
Why Not UpStudy It?
Select your plan below
Premium

You can enjoy

  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to answer and
    solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic
  • Limited Solutions