Topic
Q:
3. What is the equatlon that Marcia could use to
calculate the area of the parallelogram she
drew?
A. \( A=\frac{1}{2}(14)(6) \)
B. \( A=\frac{1}{2}(14+5) \)
C. \( A=14+6 \)
D. \( A=(14)(6) \)
4. What is the area of Marcia's parallologram?
Q:
for each.
Vicky is given a rectangle with a length of 12
mm and a height of 14 mm .
1. Which equation can be used to determine \( A \),
the area of the rectangle?
A. \( A=12+14 \)
B. \( A=12(14) \)
C. \( A=\frac{1}{2} 12(14) \)
D. \( A=\frac{1}{2}(12+14) \)
2. What is the area of Vicky's rectangle?
Q:
17) through: \( (4,2) \), parallel to \( y=-\frac{3}{4} x-5 \)
Q:
3. Una ventana tiene forma rectangular y está coronada con un semicirculo. El rectángulo es de
vidrio transparente, mientras que el semicirculo es de vidrio polarizado, y deja pasar solo la mitad
de luz por unidad de área en comparación con el vidrio transparente. El perimetro de la ventana
es de 170 cm . Obtén las proporciones de la ventana que dejen pasar la mayor cantidad de luz.
Ignora el espesor del marco.
Q:
- Konstruiere ein rechtwinkliges Dreieck \( A B C \) mit der Hypotenuse \( c=9 \mathrm{~cm} \)
und der Höhe \( h_{c}=4 \mathrm{~cm} \).
- Strecke das Dreieck vom Inkreismittelpunkt aus mit \( k=-0.5 \).
Q:
Question 4
Suppose the SC DOT wants to create a new road in Lancaster County at the point \( (-5,-7) \). This new road will be perpendicular to a
current road modeled by \( y-6=-5(2 x+3) \). Find the Standard Form of the Linear Equation and Slope Intercept Form of the Line.
Use the editor to formot ydur answer
Q:
If \( P=(8,2) \), find the image
of \( P \) under the following rotation.
\( 270^{\circ} \) counterclockwise about the
origin
([?], \( \square) \)
Enter the number that belongs in
the green box.
Q:
If \( \mathrm{P}=(2,-1) \), find the image
of P under the following rotation.
\( 90^{\circ} \) counterclockwise about the origin
\( ([?],[]) \)
Enter the number that belongs in
the green box.
Q:
a) \( (3,9)+(6,-4) \)
Q:
parallel, perpendicular, or neither:
\[ 5 . \quad m_{1}=-1 / 2 \quad m_{2}=2 \]
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