Q:
Jomework
According to fightstats.com, American Airlines flights from Dallas to Chicago are on time \( 80 \% \) of the tin
(a) Explain why this is a binomial experiment.
(b) Determine the values of \( n \) and p .
(c) Find and interpret the probability that exactly 9 flights are on time.
(d) Find and interpret the probability that fewer than 9 flights are on time.
(e) Find and interpret the probability that at least 9 flights are on time.
(f) Find and interpret the probability that between 7 and 9 flights, inclusive, are on time.
(a) Identify the statements that explain why this is a binomial experiment. Select all that apply.
Q:
A binomial probability experiment is conducted with the given parameters. Comput
\[ n=11, p=0.3, x \leq 4 \]
The probability of \( x \leq 4 \) successes is \( \square \). (Round to four decimal places as needed.)
Q:
3. A bag of marbles contains 9 red, 7 purple, 6
blue, and 3 yellow marbles. If pulling one
marble out of the bag, what is the probability of
choosing a purple marble?
Q:
A binomial probability experiment is conducted with the given parameters. Compute the probability of \( x \) successes in the \( n \) indepe
\( n=10, p=0.2, x \leq 4 \)
The probability of \( x \leq 4 \) successes is 6.9671 . (Round to four decimal places as needed.)
Q:
The pieces of candy in Paul's bag of candy have
the following colors:
40 red \( \quad 30 \) blue \( \quad 30 \) yellow
\( \begin{array}{l}\text { If Paul's friends selected a piece of candy at } \\ \text { random today, what is the probability that he will } \\ \text { select a red piece of candy? }\end{array} \)
Q:
20. A bag contains one red marble, one green
marble, and one blue marble. You randomly
pick a marble and keep it to play with. Then
your friend picks a marble from the bag.
Q:
A bag contains one red marble and two green
marbles. You randomly pick a marble and keep
it to play with. Then your friend picks a marble
from the bag.
Q:
Porording to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267 . Suppos
they sneeze. Complete parts (a) through (c).
(a) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, exactly 5 do not cover their mouth when sneezing?
The probability is 0.1945 .
(Round to four decimal places as needed.)
(b) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, fewer than 4 do not cover their mouth when sneezing?
The probability is 0.6925 .
(Round to four decimal places as needed.)
Q:
According to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267 , Suppose
they sneeze. Complete parts (a) through (c).
(a) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, exactly 5 do not cover their mouth when sneezing?
The probability is 0.1945 .
(Round to four decimal places as needed.)
(b) Using the binomial distribution, what is the probability that among 16 randomly observed individuals, fewer than 4 do not cover their mouth when sneezing?
The probability is
(Round to four decimal places as needed.)
Q:
8. A soccer player takes two penalty kicks in a
game. Each attempt results in a goal or a miss.
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