Topic
Q:
Question \( 4(0.25 \) points) Retake question \( \checkmark \) Saved
Select all the ways that one could correctly write a confidence interval.
point estimate \( \pm \) margin of error
\( (0.035,0.145) \)
\( \widehat{p} \pm 1.96^{*} S E \)
Q:
A local TV station wished to determine if a higher proprotion of women watch the local news. They conduct
a survey of 200 women and 200 men. Of those surveyed, \( 59 \% \) of women and \( 51 \% \) of men say they watch
the local news.
Find the P-value: Type your answer as a decimial rounded to three decimal places. Do not type a
percentage or a percent sign.
P-value=
Q:
Question 4 ( 0.25 points) Retake question
Select all the ways that one could correctly write a confidence interval.
point estimate \( \pm \) margin of error
\( (0.035,0.145) \)
\( \widehat{p} \pm 1.96^{*} S E \)
Q:
1d) sample standard deviation =
2) Compute: \( p(0.8<z<2.19) \). You must sketch, shade, and label a bell curve for credit.
Q:
Question 2 ( 0.25 points) Retake question
What is the \( z^{*} \) value for a \( 95 \% \) confidence interval?
1.96
2.58
\( \pm 1.96 \)
Q:
6.3. A survey was conducted at Malamulele Secondary School to establish how
many of the 650 learners buy vetkoek and how many buy muffins in the morning.
The following was found
- 50 leaners bought nothing
- 400 learners bought vetkoek
6.3.1. Represent the information on a Venn diagram.
6.3.2. How many learners bought both the vetkoek and the muffin?
6.3.3. If a learner is chosen at random, calculate the probability of a learner that
does not buy muffins as a percentage.
Q:
Exercise 1: One hundred subjects in a psychological study had a mean score of \( M=35 \) on a
test instrument designed to measure anger. The standard deviation of the \( n=100 \) test scores
was \( \sigma=10 \). Find:
a. A \( 99 \% \) confidence interval for the mean of the population the sample was selected.
b. A \( 95 \% \) confidence interval for the mean of the population the sample was selected.
c. A \( 96 \% \) confidence interval for the mean of the population the sample was selected.
d. A \( 80 \% \) confidence interval for the mean of the population the sample was selected
Q:
Exercise 1: One hundred subjects in a psychological study had a mean score of \( M=35 \) on a
test instrument designed to measure anger. The standard deviation of the \( =100 \) test scores
was \( \sigma=10 \). Find:
a. A \( 99 \% \) confidence interval for the mean of the population the sample was selected.
b. A \( 95 \% \) confidence interval for the mean of the population the sample was selected.
c. A \( 96 \% \) confidence interval for the mean of the population the sample was selected.
d. A \( 80 \% \) confidence interval for the mean of the population the sample was selected
Q:
Una encuesta respondida por 1.000 estudiantes de un colegio A concluye que 726 no tie
hábito de lectura. En otro colegio B se realizó la misma encuesta a 760 estudiantes, c
cluyéndose que 240 de ellos tienen hábito de lectura. Calcule un intervalo de confianza
\( 95 \% \) para la diferencia entre la proporción de estudiantes que tienen hábito de lectura en
las dos encuestas. ¿Hay una diferencia significativa?
Q:
Exercise I: One hundred subjects in a psychological study had a mean score of \( M=35 \) on a
test instrument designed to measure anger. The standard deviation of the \( n=100 \) test scores
was \( \sigma=10 \). Find:
a. A \( 99 \% \) confidence interval for the mean of the population the sample was selected.
b. A \( 95 \% \) confidence interval for the mean of the population the sample was selected.
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