The polynomial of degree $$ 4, P(x) $$, has a root of multiplicity 2 at $$ x=3 $$ and roots of multiplicity 1 at $$ x=0 $$ and $$ x=-1 $$. It goes through the point $$ (5,12) $$. Find a formula for $$ P(x) $$. $$ P(x)=\square $$

Question

Simmons Campos · Accepted Answer

$$ P(x) = \frac{1}{10}x^4 - \frac{1}{2}x^3 + \frac{3}{10}x^2 + \frac{9}{10}x $$

The polynomial of degree \( 4, P(x) \), has a root of multiplicity 2 at \( x=3 \) and roots of multiplicity 1 at \( x=0 \) and \( x=-1 \). It goes through the point \( (5,12) \). Find a formula for \( P(x) \). \( P(x)=\square \)

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The polynomial of degree \( 4, P(x) \), has a root of multiplicity 2 at \( x=3 \) and roots of multiplicity 1 at \( x=0 \) and \( x=-1 \). It goes through the point \( (5,12) \). Find a formula for \( P(x) \). \( P(x)=\square \)

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