$$ f(x)-x^{2}-5 x+2 $$ Solve for $$ x $$ if $$ f(x)=0 $$ For which values of $$ c $$ will $$ f(x)=c $$ have no real roots? for $$ x $$ and $$ y $$ :

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To solve $$ f(x) = 0 $$, set $$ x^{2} + 5x - 2 = 0 $$ and find the solutions: $$ x = \frac{-5 + \sqrt{33}}{2} \quad \text{and} \quad x = \frac{-5 - \sqrt{33}}{2} $$ For $$ f(x) = c $$ to have no real roots, $$ c $$ must be less than -8.25.

\( f(x)-x^{2}-5 x+2 \) Solve for \( x \) if \( f(x)=0 \) For which values of \( c \) will \( f(x)=c \) have no real roots? for \( x \) and \( y \) :

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\( f(x)-x^{2}-5 x+2 \) Solve for \( x \) if \( f(x)=0 \) For which values of \( c \) will \( f(x)=c \) have no real roots? for \( x \) and \( y \) :

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Solución paso a paso

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