Which of the following is a solution to the inequality below? \( 3+4 d \leq 42 \) \( d=10 \) \( d=11 \) \( d=2 \)

\( 3 x-2 y=7 \) (1) \( y+2 y=14 \) (2)

4. Make \( c \) the subject of \( g=\frac{c+3}{4+c}-7 \)

3. Question 3. Solve \( x-5=3 x+2 \)

Three consecutive numbers their sum is 48 write an equation express that is .... \( \begin{array}{l}3 x+2=48 \\ 3 x+4=48 \\ 3 x+3=48 \\ 3 x-3=48\end{array} \)

Add \( 5 \mathrm{a}-3 \mathrm{~b} \) and \( -5 \mathrm{~b}+3 \mathrm{a} \) the result is ...... \[ \begin{array}{l}8 \mathrm{a}-8 \mathrm{~b} \\ 8 \mathrm{a}+8 \mathrm{~b} \\ 8 \mathrm{~b}-8 \mathrm{a} \\ 2 \mathrm{a}-2 \mathrm{~b}\end{array} \]