What is the value of \( \left(\frac{1}{2}\right)^{3} \) ?

Укажите число, обратное числу \( 4 \frac{1}{4} \) : \( \begin{array}{l}\text { а) } 1 ; \text { б) } \frac{1}{4} ; \text { в) } 0 ; \text { г) } \frac{4}{17} \text {; д) } 4,25 \text {. }\end{array} \)

3. Ivaluato without using calculator a) \( \frac{-12 \div(-3) \times 4-(-20)}{-6 \times 6 \div 3+(-6)} \) b) \( \frac{-4+(-3) \text { of } 9+1 \times 14 \div 2)}{4+2 \text { of } 3-(-10 \div 5)} \) Simplify \( \frac{6}{7}+4 \frac{4}{5} \times 1 / 6 \div 1 / 6 \) \( 8 / 11-4 / 5 \times 2 / 6 \)

\( 1+6+11+16+.....+56 \)

2. 6 If two positive integers \( a \) and \( b \) are written as \( a=x^{3} y^{2} \) and \( b=x y^{3} \), where \( x, y \) are prime numbers, then HCF \( (a, b) \) is \( \begin{array}{llll}\text { (a) } x y & \text { (b) } x y^{2} & \text { (c) } x^{2} y^{3} & \text { (d) } x^{2} y^{2}\end{array} \) \( \begin{array}{ll}\text { (b) Given that, } & a=x^{3} y^{3}=x \times x \times x \times y \times y \\ \text { and } & b=x y^{3}=x x y x y \times y\end{array} \)

number, or phrase. Lucy (she/her) has 6 sisters and she also has 9 brothers. What is the number of sisters that Lucy's brother has?