The function \( f(x)=-0.25 x \) is negative at \( x \in \)

\( 67.04 \mathrm{~cm}^{2}=\frac{\sqrt{269}}{2} h \) what is h ?

\[ S_{n}=-6+2+10+18+\ldots \] to \( n \) terms. 1. We can find an expression for the general term of the series in the form \( T_{k}=b k+c \). What are the values of \( b \) and \( c \) ? Answer: 1. \( b= \)

\( \left\{ \left. \begin{array} { l } { a - 5 < 2 a + 3 } \\ { 3 a - 2 < a - 6 } \end{array} \right. \Rightarrow a \in ? \right. \)

\( 67.04 cm ^ { 2 } = \frac { \sqrt { 26 a } } { 2 } h \)

13 If \( \frac{a}{b}=\frac{b}{c}=2 \), then \( \frac{a}{c}=\ldots \ldots \ldots \ldots \) \( \begin{array}{lll}\text { (a) } 2 & \text { (b) } 4 & \text { (c) } 6\end{array} \)