$$ \left. \begin{array} { c } { \log _ { 2 } ( a + 3 b ) = 0 } \ { 2 + 2 \log _ { 4 } a = \log _ { 4 } 6 ( a + b ) } \end{array} ight. $$

Question

$$ \left. \begin{array} { c } { \log _ { 2 } ( a + 3 b ) = 0 } \ { 2 + 2 \log _ { 4 } a = \log _ { 4 } 6 ( a + b ) } \end{array} ight. $$

Sullivan Hobbs · Accepted Answer

The solution is $$ a = \frac{1}{2} $$ and $$ b = \frac{1}{6} $$.

\( \left. \begin{array} { c } { \log _ { 2 } ( a + 3 b ) = 0 } \\ { 2 + 2 \log _ { 4 } a = \log _ { 4 } 6 ( a + b ) } \end{array} \right. \)