(3) The result of $$ \int \operatorname{Sin}^{3} x \operatorname{Cos} x d x $$ is: $$ \begin{array}{llll}\text { (A) } \frac{1}{4} \operatorname{Sin}^{4} x+c & \frac{-1}{4} \operatorname{Sin}^{4} x+c & \text { (C) } \operatorname{Sin}^{4} x+c & \text { (D) }-\operatorname{Sin}^{4} x+c\end{array} $$

Question

Deleon Chan · Accepted Answer

The integral of $$ \sin^{3} x \cos x \, dx $$ is $$ \frac{1}{4} \sin^{4} x + C $$. So, the correct answer is (A) $$ \frac{1}{4} \sin^{4} x + C $$.

(3) The result of \( \int \operatorname{Sin}^{3} x \operatorname{Cos} x d x \) is: \[ \begin{array}{llll}\text { (A) } \frac{1}{4} \operatorname{Sin}^{4} x+c & \frac{-1}{4} \operatorname{Sin}^{4} x+c & \text { (C) } \operatorname{Sin}^{4} x+c & \text { (D) }-\operatorname{Sin}^{4} x+c\end{array} \]

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Solución paso a paso

(3) The result of \( \int \operatorname{Sin}^{3} x \operatorname{Cos} x d x \) is: \[ \begin{array}{llll}\text { (A) } \frac{1}{4} \operatorname{Sin}^{4} x+c & \frac{-1}{4} \operatorname{Sin}^{4} x+c & \text { (C) } \operatorname{Sin}^{4} x+c & \text { (D) }-\operatorname{Sin}^{4} x+c\end{array} \]

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Respuesta rápida

Solución paso a paso

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