Question Evaluate the following limit using L'Hospital's rule. $$ \lim _{x \rightarrow 0^{+}}\left(\frac{1}{9 x}\right)^{\left(\frac{1}{4 \ln (6 x)}\right)} $$ Provide your answer below: $$ \lim _{x \rightarrow 0^{+}}\left(\frac{1}{9 x}\right)^{\left(\frac{1}{4 \ln (6 x)}\right)}=\square $$

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Ingram Marshall · Accepted Answer

The limit is $$\frac{\sqrt[4]{e^{3}}}{e}$$.

Question Evaluate the following limit using L'Hospital's rule. \[ \lim _{x \rightarrow 0^{+}}\left(\frac{1}{9 x}\right)^{\left(\frac{1}{4 \ln (6 x)}\right)} \] Provide your answer below: \( \lim _{x \rightarrow 0^{+}}\left(\frac{1}{9 x}\right)^{\left(\frac{1}{4 \ln (6 x)}\right)}=\square \)

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Question Evaluate the following limit using L'Hospital's rule. \[ \lim _{x \rightarrow 0^{+}}\left(\frac{1}{9 x}\right)^{\left(\frac{1}{4 \ln (6 x)}\right)} \] Provide your answer below: \( \lim _{x \rightarrow 0^{+}}\left(\frac{1}{9 x}\right)^{\left(\frac{1}{4 \ln (6 x)}\right)}=\square \)

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