8. If $$ f(x)=x^{2}+10 \sin x $$, show that there is a number $$ c $$ such that $$ f(x)=1000 $$.

Question

Howell Murray · Accepted Answer

Using the Intermediate Value Theorem, we find that $$ f(31) < 1000 < f(32) $$ for the function $$ f(x) = x^2 + 10 \sin x $$. Therefore, there exists a number $$ c $$ in the interval $$ (31, 32) $$ where $$ f(c) = 1000 $$.

8. If \( f(x)=x^{2}+10 \sin x \), show that there is a number \( c \) such that \( f(x)=1000 \).

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8. If \( f(x)=x^{2}+10 \sin x \), show that there is a number \( c \) such that \( f(x)=1000 \).

Solución ThothAI de Upstudy

Respuesta rápida

Solución paso a paso

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