Solve for \( x \) : \( \begin{array}{ll}2.1 .1 & p x+q x=a \\ 2.1 .2 & 2 x^{2}-5 x+2=0 \\ 2.1 .3 & (1-1)^{3 x+1}=32\end{array} \)

Write an equation that expresses the following relationship. \( u \) varies directly with \( p \) and inversely with \( d \) In your equation, use \( k \) as the constant of proportionality. पा]

Write an equation that expresses the following relationship. \[ d \text { varies directly with } w \text { and inversely with the square root of } p \] In your equation, use \( k \) as the constant of proportionality.

Write an equation that expresses the following relationship. \( w \) varies directly with the cube of \( u \) and inversely with \( d \) In your equation, use \( k \) as the constant of proportionality,

a. \( x^{2}=49 \)

○39.5. а) \( \left\{\begin{array}{l}x-3 y=5, \\ 3 x+2 y=4 ;\end{array}\right. \) б) \( \left\{\begin{array}{l}3 x+y=1, \\ 2 x-5 y=-22 ;\end{array}\right. \) о39.6. а) \( \left\{\begin{array}{l}x+y=4, \\ 4 x-5 y=7 ;\end{array}\right. \) б) \( \left\{\begin{array}{l}x-y=6, \\ 5 x-2 y=-3 ;\end{array}\right. \) о39.7. а) \( \left\{\begin{array}{l}40 x+3 y=-10, \\ 20 x-7 y=-5 ;\end{array}\right. \) б) \( \left\{\begin{array}{l}5 x+2 y=1, \\ 15 x+3 y=3 ;\end{array}\right. \)