12-variant 1. $$ A(4 ; 3 ;-2), B(-3 ;-1 ; 4), C(2 ; 2 ; 1\} ; $$ $$ a=\overrightarrow{A B}, b=\overrightarrow{A C}, c=\overrightarrow{C B}, d=2 c-5 b, \quad l=C B, \alpha=4, \beta=3 $$

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Washington Dunn · Accepted Answer

Berilgan nuqtalar koordinatalari: - $$ A(4,\; 3,\; -2) $$ - $$ B(-3,\; -1,\; 4) $$ - $$ C(2,\; 2,\; 1) $$ Vektorlarni hisoblaymiz: - $$ \mathbf{a} = \overrightarrow{AB} = (-7,\; -4,\; 6) $$ - $$ \mathbf{b} = \overrightarrow{AC} = (-2,\; -1,\; 3) $$ - $$ \mathbf{c} = \overrightarrow{CB} = (-5,\; -3,\; 3) $$ - $$ \mathbf{d} = 2\mathbf{c} - 5\mathbf{b} = (0,\; -1,\; -9) $$ - $$ \mathbf{l} = \overrightarrow{CB} = (-5,\; -3,\; 3) $$ Parametrlar: - $$ \alpha = 4 $$ - $$ \beta = 3 $$ Agar qo'shimcha savollar yoki hisob-kitoblar kerak bo'lsa, iltimos, aniqroq ma'lumot bering.

12-variant 1. \( A(4 ; 3 ;-2), B(-3 ;-1 ; 4), C(2 ; 2 ; 1\} ; \) \( a=\overrightarrow{A B}, b=\overrightarrow{A C}, c=\overrightarrow{C B}, d=2 c-5 b, \quad l=C B, \alpha=4, \beta=3 \)

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12-variant 1. \( A(4 ; 3 ;-2), B(-3 ;-1 ; 4), C(2 ; 2 ; 1\} ; \) \( a=\overrightarrow{A B}, b=\overrightarrow{A C}, c=\overrightarrow{C B}, d=2 c-5 b, \quad l=C B, \alpha=4, \beta=3 \)

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