\begin{tabular}{l}$$ 105 x^{2}-3 x y+3 x-2 y^{2}+4 y=5 $$ and $$ y+2 x=1 $$ \ $$ 11 y=(x+2)^{2}-5 $$ and $$ y=\frac{4}{x} \quad $$ Factorise your eq \ \hline\end{tabular}

Question

Stephens Simmons · Accepted Answer

To factorize the equations, first simplify them: 1. $$105x^2 - 3xy + 3x - 2y^2 + 4y - 5 = 0$$ 2. $$y + 2x - 1 = 0$$ 3. $$11y = x^2 + 4x - 1$$ 4. $$y = \frac{4}{x}$$ These equations can be factored by solving for one variable in terms of the other and substituting back.

\begin{tabular}{l}\( 105 x^{2}-3 x y+3 x-2 y^{2}+4 y=5 \) and \( y+2 x=1 \) \\ \( 11 y=(x+2)^{2}-5 \) and \( y=\frac{4}{x} \quad \) Factorise your eq \\ \hline\end{tabular}

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\begin{tabular}{l}\( 105 x^{2}-3 x y+3 x-2 y^{2}+4 y=5 \) and \( y+2 x=1 \) \\ \( 11 y=(x+2)^{2}-5 \) and \( y=\frac{4}{x} \quad \) Factorise your eq \\ \hline\end{tabular}

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Solución paso a paso

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