\( \sin ( 2 x + \frac { \pi } { 6 } ) = \cos x + \cos ( x + \frac { \pi } { 6 } ) \sin x \)

2. El angule \( 60^{\circ} \) equivale en radianes a: \( \begin{array}{ll}\text { A. } \frac{2}{3} \pi \mathrm{rad} & \text { C. } 3 \pi \mathrm{rad} \\ \text { B. } \frac{1}{3} \pi \mathrm{rad}, & \text { D. } \frac{1}{6} \pi \mathrm{rad}\end{array} \)

\( \frac { \sin ^ { 2 } ( 180 + x ) \cdot \sqrt { \operatorname { cosec } ^ { 2 } ( 360 - x ) - 1 } } { \sqrt { 1 + \tan ^ { 2 } ( 360 - x ) } \cdot \cos ( 360 - x ) \cdot \cot ( 180 + x ) } \)

\( = \sqrt { ( \operatorname { Sen } ^ { 2 } x - \operatorname { Cos } ^ { 2 } x ) ( \operatorname { Sen } ^ { 4 } x + \operatorname { Cos } ^ { 4 } x ) + \operatorname { Cos } ^ { 8 } x } \)

5) \( \operatorname{sen}^{2}\left(x^{2}+3\right)+\cos ^{2}\left(x^{2}+3\right) \)

Question From the observation deck of a skyscraper, Bentley measures a \( 48^{\circ} \) angle of depression to a ship in the harbor below. If the observation deck is 969 feet high, what is the horizontal distance from the base of the skyscraper out to the ship? Round your answeir to the nearest tenth of a foot if necessary.