Expand $$ \sin x $$ in powers of $$ \left(x-\frac{\pi}{2}\right) $$

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Matthews Guzman · Accepted Answer

The expansion of $$ \sin x $$ in powers of $$ \left(x - \frac{\pi}{2}\right) $$ is: $$ \sin x = 1 - \frac{(x - \frac{\pi}{2})^2}{2!} + \frac{(x - \frac{\pi}{2})^4}{4!} - \frac{(x - \frac{\pi}{2})^6}{6!} + \cdots $$

Expand \( \sin x \) in powers of \( \left(x-\frac{\pi}{2}\right) \)

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Expand \( \sin x \) in powers of \( \left(x-\frac{\pi}{2}\right) \)

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Solución paso a paso

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