Question: a. Solve $$ 2 \cos heta=-\sqrt{2} $$ on $$ [0,2 \pi) $$ b. Solve $$ an heta=\sqrt{3} $$ on $$ [0,2 \pi) $$

Question

Question: a. Solve $$ 2 \cos 	heta=-\sqrt{2} $$ on $$ [0,2 \pi) $$ b. Solve $$ 	an 	heta=\sqrt{3} $$ on $$ [0,2 \pi) $$

Logan Sanders · Accepted Answer

a. $$ 	heta = \frac{3\pi}{4} + 2k\pi $$ and $$ 	heta = \frac{5\pi}{4} + 2k\pi $$ b. $$ 	heta = \frac{\pi}{3} + k\pi $$

Question: a. Solve \( 2 \cos \theta=-\sqrt{2} \) on \( [0,2 \pi) \) b. Solve \( \tan \theta=\sqrt{3} \) on \( [0,2 \pi) \)