2. For the equation $$ \cos 2 x=-0.32 $$ a) solve for $$ x $$, where $$ 0 \leq x

Question

2. For the equation $$ \cos 2 x=-0.32 $$ a) solve for $$ x $$, where $$ 0 \leq x<2 \pi $$ $$ \arccos (-0.32) \approx 1.8925 $$ radians $$ 2 \pi-1.8925 \approx 4.3907 $$ b) determine the general solution.

Robbins Daniels · Accepted Answer

The general solution for $$ x $$ in the equation $$ \cos 2x = -0.32 $$ is: $$ x = \pm \frac{\arccos(-0.32)}{2} + \pi n \quad \text{for any integer } n $$

2. For the equation \( \cos 2 x=-0.32 \) a) solve for \( x \), where \( 0 \leq x<2 \pi \) \( \arccos (-0.32) \approx 1.8925 \) radians \[ 2 \pi-1.8925 \approx 4.3907 \] b) determine the general solution.

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Solución paso a paso

2. For the equation \( \cos 2 x=-0.32 \) a) solve for \( x \), where \( 0 \leq x<2 \pi \) \( \arccos (-0.32) \approx 1.8925 \) radians \[ 2 \pi-1.8925 \approx 4.3907 \] b) determine the general solution.

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Respuesta rápida

Solución paso a paso

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