\( \begin{array}{ll}\text { 1) } y=\left(9 x^{3}-5\right)^{4} & \text { 6) } y=(3 \operatorname{sen} x)^{3} \\ \text { 2) } y=(2 \tan 3 x)^{3} & \text { 1) } y=\frac{1}{(5 x-2)} \\ \text { 3) } y=\frac{1}{(\cos 5 x)^{2}} & \text { 8) } y=\left(7 x^{2}+3 x\right)^{4} \\ \text { 4) } y=(6 x+3)^{2} & \text { a) } y=(8 x+7)^{2} \\ \text { 5) } y=\left(12 x^{2}+4 x\right)^{3} & \text { 10) } y=\left(5 x^{3}+2 x\right)^{-1}\end{array} \)

Encontrar \( f(t) \) si \( \rho(s)=\frac{s}{s^{2}+6 s+10} \)

\( \int \frac { \operatorname { cen } x d x } { \cos x ( \cos x - 1 ) } \)

Ercontrar \( f(t) \) si \( F(s)=\frac{5}{s^{2}+4}+\frac{20 s}{s^{2}+9} \)

Find the value. \[ \begin{array}{l}\operatorname{In}\left(\frac{92}{20}\right) \\ \text { In }\left(\frac{92}{20}\right) \approx \square \\ \text { (Round the final answer to four decimal places as needed. Round }\end{array} \]

One measure of living standards in country \( A \) is given by the following formula \( L(t)=7+4 e^{0.14 t} \) In this formula \( t \) is the number of years since 1982. Find \( L \) to the nearest hund \( \begin{array}{ll}\text { (a) } 1988 & \text { (b)1998 } \\ \text { (c)2007 }\end{array} \) \( \begin{array}{l}\text { (a) Find } L \text { for } 1988 . \\ \text { (Round to the nearest hundredth as needed.) } \\ \text { (b) Find } L \text { for } 1998 . \\ L=\square\end{array} \) (Round to the nearest hundredth as needed.) (c) Find \( L \) for 2007 .