$$ f(x)=\frac{|x|}{x}=\left\{\begin{array}{lr}3 x-1, & x3, \ \mathrm{x}^{2}-2, & -2 \leq x \leq 3 \ 2 x+3, & x

Question

$$ f(x)=\frac{|x|}{x}=\left\{\begin{array}{lr}3 x-1, & x>3, \ \mathrm{x}^{2}-2, & -2 \leq x \leq 3 \ 2 x+3, & x<-2,\end{array}\right. $$ d the values of $$ f(2), f(4), f(-1), f(-3) $$ and $$ \mathrm{f}(0) $$.

Lang Todd · Accepted Answer

$$ f(2) = 2 $$, $$ f(4) = 11 $$, $$ f(-1) = -1 $$, $$ f(-3) = -3 $$, $$ f(0) = -2 $$.

\[ f(x)=\frac{|x|}{x}=\left\{\begin{array}{lr}3 x-1, & x>3, \\ \mathrm{x}^{2}-2, & -2 \leq x \leq 3 \\ 2 x+3, & x<-2,\end{array}\right. \] d the values of \( f(2), f(4), f(-1), f(-3) \) and \( \mathrm{f}(0) \).

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Solución paso a paso

\[ f(x)=\frac{|x|}{x}=\left\{\begin{array}{lr}3 x-1, & x>3, \\ \mathrm{x}^{2}-2, & -2 \leq x \leq 3 \\ 2 x+3, & x<-2,\end{array}\right. \] d the values of \( f(2), f(4), f(-1), f(-3) \) and \( \mathrm{f}(0) \).

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Respuesta rápida

Solución paso a paso

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