15. Suppose data collected for heights (in cms) of 390 cows were tabulated in a frequency distribution and the following results were obtained. fi: \( 6,25,48,72,116,60,38,22,3 \) CMI \( =112, \mathrm{CM} 2=117 \) where CMi ith class mark Determine: a) Class interval size (class width), Class limits, Class boundaries and class marks b) The less than cumulative frequency distribution c) The class intervals having the highest frequency d) Above which height do we find \( 50 \% \) of the cows? c) Below which height do we get \( 25 \% \) of the cows? Draw a) histogram b) a frequency polygon c) C. a less than ogive for the above data

15. Suppose data collected for heights (in cms) of 390 cows were tabulated in a frequency distribution and the following results were obtained. fi: \( 6,25,48,72,116,60,38,22,3 \) CMI \( =112, \mathrm{CM} 2=117 \) where CMi ith class mark Determine: a) Class interval size (class width), Class limits, Class boundaries and class marks b) The less than cumulative frequency distribution c) The class intervals having the highest frequency d) Above which height do we find \( 50 \% \) of the cows? c) Below which height do we get \( 25 \% \) of the cows? Draw a) histogram b) a frequency polygon c) C. a less than ogive for the above data

The mean weight of 150 students in a certain class is 60 Kg . The mean weight of boys in the class is 70 Kg and that of the girls is 55 Kg 。 Find the number of boys and the number of girls in the class.

Which sampling Which sampling method is better? Why? Which sampling method you might use in Assignment \# 2 (Marketing Dashboard)? Why?

61. Mode is the value with maximum frequency in the data. 62. Fermions are classified as Leptons and Baryons. 63. A muxture in which the composition is not uniform throughout is called heterogeneous mixture 64. The arithmetic mean of first ' \( n \) ' natural numbers is \( \frac{n}{2} \) ' 65. Symmetric encryption is slower than asymmetric encryption. 66. \( |7|=0 \)

(b) Hitung sisihan piawai bagi tinggi, dalam cm , murid tingkatan 5 Kristal dengan diteri silai min ketinggian murid tersebut adalah 155.5 cm . Calculate the standard deviation of the height, in cm , of pupils in form 5 Kristal by given the mean value of the height of the pupils is 155.5 cm . [3 markah/ marks] (c) Dengan menggunakan skala 2 cm kepada 5 cm pada paksi mengufuk dan 2 cm kepada seorang murid pada paksi mencancang, lukis histogram bagi maklumat tersebut. Using a scale of 2 cm to 5 cm on the horizontal axis and 2 cm to a pupil on the vertical cris, draw a histogram for the information.