\( \left. \begin{array} { l } { \operatorname { Step } 1 : \frac { c = 2 \pi r } { C = 2 \cdot \pi \cdot 6 } } \\ { \operatorname { Step } 2 : \frac { c } { C = 12 \pi } } \end{array} \right. \)

Question If you place a 28 -foot ladder against the top of a 22-foot building, how many feet will the bottom of the ladder be from the bottom of the building? Round to the nearest tenth of a foot. Answer Attempt 1 out of 2

\( \left.\begin{array}{l}2 \text { In un rombo } A B C D \text { la diagonale } A C \text { forma un ango- } \\ \text { lo di } 74^{\circ} 38^{\prime} \text { con il lato } A D . \text { Quanto misurano gif } \\ \text { angoli del rombo? } \\ {\left[149^{\circ} 16^{\prime} ; 30^{\circ} 44^{\prime} ; . . . . . .\right]}\end{array}\right] \),

Whoose the correct answer? (1) if \( A(3,5), B(7,1) \) and \( C \) is the midpoint of \( \overline{A B} \) then \( C= \).

In the diagram, \( Q R \| S T, T \hat{S} R=42^{\circ}, U \hat{T} V=82^{\circ}, S \hat{T} R=y, S \hat{R} Q=x \), and \( T \hat{R} S=x+40^{\circ} \)

3. Calcola l'area del rettangolo \( A B C D \) sapendo che \( B D=35 \mathrm{~cm} \) e \( C H=16,8 \mathrm{~cm} \). \( \quad\left[588 \mathrm{~cm}^{2}\right] \)