\( \frac{a+b}{5}=\frac{b+c}{3}=\frac{c+a}{6} \), prove that \( : \frac{a+b+c}{a-c}=\frac{7}{2} \)

b. \( \frac{1}{3} \times(\sqrt{5}-\sqrt{2}) \times(\sqrt{5}+\sqrt{2}) \)

Move Variables to one side

\begin{tabular}{c}\hline SOLVING EQUATIONS \\ \hline \( \begin{array}{c}\text { Simplify Each Side } \\ \text { by combining like terms }\end{array} \) \\ \hline \( \begin{array}{c}\text { Move Variables } \\ \text { to one side }\end{array} \) \\ \hline Solve \\ \hline Using inverse operations \\ \hline\end{tabular}

1. \( \left(2 \frac{1}{4} x^{6} y^{2}\right) \cdot\left(-\frac{2}{3} x y^{3}\right)^{2} \cdot\left(3 x^{5} y^{2}\right)^{3} \) birhadlisininquavatila amsali farqinitapin. \( \begin{array}{llll}\text { A) } 5 & \text { B) } 13 & \text { (C) } 10 & \text { D) } 18\end{array} \)

6. \( A=5 a^{2}-2 a b-3 b^{2}, B=3 a^{2}+2 a b+b^{2} \) olarsa, \( A-(B-2 A-(2 B-2 A))- \) nitapin. \( \begin{array}{llll}\text { A) } 2 a^{2}-4 a b & \text { B) } 8 a^{2}-2 b^{2} & \text { C) } 8 a^{2}-4 b^{2} & \text { D) } 2 a^{2}-4 b^{2}\end{array} \)