40) If the function $$ f $$ is continuous, $$ f(5)=9, f(1)=4 $$ then $$ \int_{1}^{5} \sqrt[3]{f(x)} imes f^{\prime}(x) d x= $$ $$ \begin{array}{llll} ext { a) } 19 & ext { b) } 38 & ext { c) } 10 \sqrt{3}-2 & ext { d) } 50\end{array} $$

Question

40) If the function $$ f $$ is continuous, $$ f(5)=9, f(1)=4 $$ then $$ \int_{1}^{5} \sqrt[3]{f(x)} 	imes f^{\prime}(x) d x= $$ $$ \begin{array}{llll}	ext { a) } 19 & 	ext { b) } 38 & 	ext { c) } 10 \sqrt{3}-2 & 	ext { d) } 50\end{array} $$

Carlson Vega · Accepted Answer

The integral $$\int_{1}^{5} \sqrt[3]{f(x)} 	imes f^{\prime}(x) \, dx$$ simplifies to $$3 	imes \sqrt[3]{9} - 2 	imes \sqrt[3]{16} - \frac{1}{3} \left( 3 	imes \sqrt[3]{9} - 2 	imes \sqrt[3]{16} ight)$$.

40) If the function \( f \) is continuous, \( f(5)=9, f(1)=4 \) then \( \int_{1}^{5} \sqrt[3]{f(x)} \times f^{\prime}(x) d x= \) \( \begin{array}{llll}\text { a) } 19 & \text { b) } 38 & \text { c) } 10 \sqrt{3}-2 & \text { d) } 50\end{array} \)

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Solución paso a paso

40) If the function \( f \) is continuous, \( f(5)=9, f(1)=4 \) then \( \int_{1}^{5} \sqrt[3]{f(x)} \times f^{\prime}(x) d x= \) \( \begin{array}{llll}\text { a) } 19 & \text { b) } 38 & \text { c) } 10 \sqrt{3}-2 & \text { d) } 50\end{array} \)

Solución ThothAI de Upstudy

Respuesta rápida

Solución paso a paso

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