\begin{tabular}{l} Question \\ Using L'Hospital's rule, determine whether \( f(x) \) or \( g(x) \) given below grows at a faster rate. \\ \( \qquad f(x)=-3 x^{2}-x-1 \) \\ \( g(x)=-x^{3}-5 x-2 \) \\ Select the correct answer below: \\ f(x) grows at a faster rate. \\ g(x) grows at a faster rate. \\ f(x) and \( g(x) \) grow at the same rate. \\ There is not enough information to determine which function grows at a faster rate. \\ \hline\end{tabular}

Soit \( f \) la fonction définie sur \( \mathbb{R}^{+} \operatorname{par} f(x)=\frac{2 \sqrt{x}}{x+1} \) Monter que \( f \) est majoréeqar 1. \( f \) est-elle bornée? Justifier votre réponse.

\( \int _ { 2 } ^ { 5 } \int _ { 0 } ^ { \pi / 2 } r \cos \theta r \sin \theta d \theta d r = \)

2. Clase 2. Encontrar las antiderivadas de: \( \begin{array}{l}\text { 1) } \mathrm{F}(\mathrm{x})=\frac{1}{x^{3}} \\ \text { 2) } \mathrm{G}(\mathrm{y})=y^{3}\left(2 y^{2}-3\right) \\ \text { 3) } \mathrm{P}(\mathrm{x})=5 \cos (2 x)-4 \tan \left(\frac{1}{2} x\right) \\ \text { 4) } \mathrm{F}(\mathrm{x})=3 x^{2} e^{2 x}\end{array} \)

find the easiest solution, please: 1) \( \frac{\lim _{2}}{\frac{x^{5}}{\sqrt[3]{x+6}-64}} x \)

find the easiest solution, please: 1) \( \frac{\lim }{12} \frac{x^{5} \sqrt[3]{x+6}-64}{x-2}= \)