1. \( \lim _{x \rightarrow 2} \frac{x-2}{x^{2}-x-2} \) \begin{tabular}{l|l|l|l|l|l|}\( x \) & 1.9 & 1.99 & 1.999 & 2 & 2.001 \\ \hline\( f(x) \) & 2.01 & 2.1 \\ \hline\end{tabular}

\( x \frac { 1 } { \sqrt { 1 - y ^ { 2 } } } \cdot y ^ { \prime } + 3 x ^ { 2 } = \frac { 1 } { 2 \sqrt { y } } \cdot y ^ { \prime } \)

\( \left. \begin{array} { l } { \int \sin ^ { \gamma } x \cos ^ { \gamma } x d x } \\ { \int \cos ^ { r } x \sin ^ { \gamma } x d x } \end{array} \right. \)

\( = \lim _ { x \rightarrow 1 } \frac { x ^ { 2 } + x - f ( 1 ) } { x - 1 } \)

A solid has a cross section perpendicular to the x-axis, which is a square with side length \(y\). If the function \(y = 2x + 1\) represents the upper boundary of the solid from \(x=0\) to \(x=3\), find its volume.

Una sucesión puede expresarse como un límite. De esta manera \( \frac{i n(n)}{n} \) es: \( \begin{array}{l}\text { a. }(\ln ) / n=-1 \\ \left.\text { b. }(\ln )^{n}\right) / n=1 \\ \text { c. }(\ln ,) / n=0 \\ \text { d. }(\ln ), n=\infty\end{array} \)