Реши пропорцию: \( \frac{135,45}{31,5}=\frac{x}{2,5} \) Ответ: \( x=\square \)

19 days of March 2015 . \( \begin{array}{llll}\text { (1) } ₹ 1530 & \text { (2) } ₹ 1260 & \text { (3) } ₹ 1620 & \text { (4) } ₹ 1710\end{array} \) \( x \propto \frac{1}{y} \). When \( y=6, x=14 \). What is the constant of variation ? \( \begin{array}{llll}\text { (1) } 94 & \text { (2) } 84 & \text { (3) } 82 & \text { (4) } 72\end{array} \) If \( x \) varies directly as \( y \), which number will replace the question

\( \begin{array}{ll}\text { 3.4. а) } x+1>0 ; & \text { в) } x+2,5<0 \\ \text { б) } x-3 \leqslant 0 ; & \text { г) } x-7 \geqslant 0 \\ \text { 3.5. а) } 2 x \geqslant 8 ; & \text { в) } 5 x>25 ; \\ \text { б) } 4 x<12 ; & \text { г) } 7 x \leqslant 42 \\ \text { 3.6. а) } 11 x>-33 ; & \text { в) }-6 x>-12 ; \\ \text { б) }-8 x \geqslant 24 ; & \text { г) } 13 x \leqslant-65 \\ \text { 3.7. } 3 x+2>0 ; & \text { в) } 4 x-5<0 \\ \text { б) }-5 x-1 \leqslant 0 ; & \text { г) }-6 x+12 \geqslant 0 \\ \text { 3.8. а) } 2 x+3 \geqslant 7 ; & \text { в) }-5 x-1>24 ; \\ \text { б) }-3 x+4<13 ; & \text { г) }-x-8 \leqslant 19 \\ \text { 3.9. а) } 5(x+2) \geqslant 4 ; & \text { в) } 6(x-1) \leqslant 11 \\ \text { б) }-2(x-3) \leqslant 5 ; & \text { г) }-3(x+4) \geqslant-2 .\end{array} \)

Given that the quadratic equation \( p x^{2}-9 q x+9 p=0 \), where \( p \) and \( q \) are constants, has two equal roots. Find \( p: q \). [2 marks.

The value of \( \frac{9^{x}\left(9^{x-1}\right)^{x}}{9^{x+1} \cdot 3^{2 x-2}}\left\{\frac{729^{\frac{1}{3}}}{81}\right\}^{-x} \div \frac{3^{a}-2^{3} \cdot 3^{a-2}}{3^{a}-3^{a-1}} \)

If \( \frac{a+b}{a}=1 \) and \( -b+a=2 \).