б) $$ \left\{\begin{array}{l}(x+3)^{2}+(2 y+1)^{2}=x^{2}+4 y^{2}+16 \ 3 y-7 x=16\end{array} ight. $$ 39.20. а) $$ \left\{\begin{array}{l}(3 a-2 b)(2 a+5 b)=0, \ 5 a-4 b+2=0\end{array} ight. $$ б) $$ \left\{\begin{array}{l}(a+2 b+1)(3 a-4 b-2)=0 \ 5 b-2 a-8=0\end{array} ight. $$ 39.21. а) $$ \left\{\begin{array}{l}(2 x-3 y)^{2}-(5 x+y)^{2}=0 \ 5 x-2 y=1\end{array} ight. $$ б) $$ \left\{\begin{array}{l}(x+4 y)^{2}-(3 x-y)^{2}=0 \ 3 x-7 y=1\end{array} ight. $$

Question

б) $$ \left\{\begin{array}{l}(x+3)^{2}+(2 y+1)^{2}=x^{2}+4 y^{2}+16 \ 3 y-7 x=16\end{array}ight. $$ 39.20. а) $$ \left\{\begin{array}{l}(3 a-2 b)(2 a+5 b)=0, \ 5 a-4 b+2=0\end{array}ight. $$ б) $$ \left\{\begin{array}{l}(a+2 b+1)(3 a-4 b-2)=0 \ 5 b-2 a-8=0\end{array}ight. $$ 39.21. а) $$ \left\{\begin{array}{l}(2 x-3 y)^{2}-(5 x+y)^{2}=0 \ 5 x-2 y=1\end{array}ight. $$ б) $$ \left\{\begin{array}{l}(x+4 y)^{2}-(3 x-y)^{2}=0 \ 3 x-7 y=1\end{array}ight. $$

Smith Barnett · Accepted Answer

Решения системы уравнений: $$ \left\{\begin{array}{l} a = -\frac{7}{3}, b = \frac{2}{3} \ a = 6, b = 4 \end{array}\right. $$

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