Jesarrolla la función polinomial racional, Jtilizando fracciones parciales: \[ \frac{11 x+21}{(x+6)(x+1)} \]

Hallar la solucion de las sig. ecuaciones. \( x^{3}+5 x^{2}+6 x=0 \) \( 3 x^{2}+12=0 \) \( x^{3}-8 x^{2}+21 x-20=0 \) \( x^{2}+25=0 \) \( x^{4}+4 x^{3}+28 x^{2}-4 x-29=0 \) \( x^{4}+3 x^{2}-10=0 \) \( x^{4}+2 x^{2}+1=0 \) \( x^{6}-9 x^{3}+8=0 \) \( 2 x^{2}-x+3=0 \)

13 Permudahkan/ Simplify \[ \begin{array}{ll}\frac{q^{3} \times\left(q^{10} r^{2}\right)^{2}}{\left(\sqrt[3]{125} q^{6} r^{2}\right)^{5}} \div \frac{(q r)^{-15}}{\left(50 q^{2} r^{4}\right)^{\frac{1}{2}}} \\ \begin{array}{ll}\text { A } \frac{\sqrt{2}}{5^{2}} q^{3} r^{9} & \text { C } \frac{\sqrt{2}}{5^{5}} q^{3} r^{9} \\ \text { B } \frac{\sqrt{2}}{25} q^{-3} r^{-9} & \text { D } \frac{25}{\sqrt{2}} q^{3} r^{9}\end{array}\end{array} \$ \]

The length of a rectangle is 11 ft less than three times the width, and the area of the rectangle is \( 42 \mathrm{ft}^{2} \). Find the dimensions of the rectangle. Length: \( \square_{\mathrm{ft}} \)

? QUESTION The area of a rectangle is \( 28 \mathrm{ft}^{2} \), and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the rectangle.

\( 2.1 .3 \quad ( \frac { 1 } { 2 } ) ^ { 3 x + 1 } = 32 \)