2. Using triple integrals in cylindrical coordinates find the value of the integral $$ \iiint_{G} \frac{z}{\sqrt{x^{2}+y^{2}}} d V $$ if $$ G $$ is the region bounded by the plane $$ z=2 $$ and the surface $$ z=x^{2}+y^{2} $$. Ans $$ \frac{16 \sqrt{2} \pi}{5} $$

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John Hammond · Accepted Answer

The value of the integral is $$ \frac{16 \sqrt{2} \pi}{5} $$.

2. Using triple integrals in cylindrical coordinates find the value of the integral \( \iiint_{G} \frac{z}{\sqrt{x^{2}+y^{2}}} d V \) if \( G \) is the region bounded by the plane \( z=2 \) and the surface \( z=x^{2}+y^{2} \). Ans \( \frac{16 \sqrt{2} \pi}{5} \)

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2. Using triple integrals in cylindrical coordinates find the value of the integral \( \iiint_{G} \frac{z}{\sqrt{x^{2}+y^{2}}} d V \) if \( G \) is the region bounded by the plane \( z=2 \) and the surface \( z=x^{2}+y^{2} \). Ans \( \frac{16 \sqrt{2} \pi}{5} \)

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