Solve, finding all solutions in \( [0,2 \pi) \) or \( \left[0^{\circ}, 360^{\circ}\right) \). \( 2 \cos x-1=-1.2814 \) The solution(s) in \( \left[0^{\circ}, 360^{\circ}\right) \) is/are \( x \approx \square \). (Type your answer in degrees. Do not include the degree symbol in your answer. Round to two decimal places as needed. Use a comma to separate answers as needed.)

24. - Prove that \( 1+\frac{\cot ^{2} \theta}{1+\operatorname{cosec} \theta}=\operatorname{cosec} \theta \)

यदी \( \tan \theta 1 \) तो \( 2 \sin \theta \cos \theta \) का मान जे ज्ञात किजिए

З треугольнике \( K B R \) проведена высота \( B D \). Ззвестно, что \( \angle B K R=20^{\circ} \mathrm{n} \angle \) \( K B R=108^{\circ} \). Определи углы треугольника \( D B R \). \( \angle B D R=\square^{\circ} ; \) \( \angle D B R=\square^{\circ} ; \)

\( \sin \alpha - i \cos \alpha \)

24. Prove that \( 1+\frac{\cot ^{2} \theta}{1+\operatorname{cosec} \theta}=\operatorname{cosec} \theta \)