10) \( ( \) Q. 4 ball. \( ) \) Umumiy ko'paytuvchini qavsdan chiqaring: \( 49 a^{7} b^{4}-35 a^{6} b^{4} \) \( \begin{array}{ll}\text { A) } 7 a^{6} b^{4}(7 a-5) & \text { B) } 7 a^{6} b^{3}(7 a-5 b) \\ \text { C) } 7 a^{6} b^{4}(a-5) & \text { D) } 7 a^{6} b^{4}(7 a+5)\end{array} \)

20. \( \left(x^{2}-25\right) \sqrt{6-2 x}=0 \)

\( \left. \begin{array} { l } { \left\{ \begin{array} { l } { 2 x - 5 \leq 3 , } \\ { 0,3 x \geq - 21 . } \end{array} \right.} \\ { \left\{ \begin{array} { l l } { 5 x - 2 \geq - 12 , } \\ { 0,5 x \leq 4 . } \end{array} \right.} \end{array} \right. \quad \left\{ \begin{array} { l } { \frac { x + 2 } { 4 } + \frac { x + 3 } { 2 } > 3 , } \\ { - x - 2 < - 3 . } \end{array} \quad \left\{ \begin{array} { l } { ( x + 5 ) ( x + 2 ) < 0 , } \\ { ( x + 2 ) ( x - 6 ) < 0 . } \\ { \frac { x - 1 } { 2 } - \frac { x - 17 } { 4 } \geq 5 , } \\ { 2 x - 3,5 > 7 . } \end{array} , \left\{ \begin{array} { l } { \frac { x - 7 } { x + 2 } < 0 , } \\ { x ^ { 2 } - 4 x - 5 > 0 ; } \end{array} \right. \right. \right. \)

22. If \( x^{2}=64 \) and \( y^{2}=27 \), the i. \( \sqrt{x^{4 / 3}+y^{4 / 3}} \)

VI. Find the solution(s) of the following system. \[ \begin{array}{r}x+y+z=1 \\ 2 x+3 y+3 z=2 \\ x+2 y+2 z=1\end{array} \] (Write the answer for the questions on your answer sheet. 10 points)

2. \( \frac{9 x}{7-6 x}=15 \)