Олон гишүүнтүүдийг үржигдэхүун болгон задал. \( \begin{array}{ll}\text { а) } a^{2}+2 a b+b^{2} & \text { г) } 2 c d+d^{2}+c^{2} \\ \text { б) } a^{2}-6 a+9 & \text { д) } x^{2}-2 x+1 \\ \text { в) } m^{2}+n^{2}-2 m n & \text { е) } 4 a^{2}+4 a+1\end{array} \)

(8) If \( L^{2} \) and \( L \) are the two roots of the equation : \( x^{2}+a x+8=0 \), then \( a=\ldots \ldots \ldots \) \( \begin{array}{llll}\text { (a) }-6 & \text { (b) } 6 & \text { (c) } 4 & \text { (d) } 8\end{array} \)

Simplify the following: (1) \( \frac{x-1}{x^{2}+3 x+2} \div\left[\frac{x-3}{x+1}-\frac{x-4}{x+2}\right] \) (2) \( \frac{\frac{6 x+5}{x-5}}{\frac{3 x+20}{x-5}+2} \) (3) \( \frac{a^{2}+\left(1-a^{2}\right)}{(1+a) a} \times \frac{(1+a) a}{a^{2}-\left(1-a^{2}\right)} \)

(i) \( 2.25 \% \) of \( x \) is 630

Simplify. \( 6 v+3 v \)

Example Solve the equation \( 2 x^{2}+4 x-10=0 \) with error precision 0.05