Química preguntas y respuestas

Calcular el calor de reacción entre el ácido sulfúrico con hidróxido de sodio e hidróxido de amonio, y del ácido nítrico con hidróxido de amonio e hidróxido de sodio. Tenga en cuenta que entra un flujo de 10L/min del ácido a una concentración de 1,5M

Consider the following reaction: \( \mathrm{NH}_{4}^{+}+\mathrm{CN}^{\cdot} \Leftrightarrow \mathrm{NH}_{3}+\mathrm{HCN} \) Which pair of substances represents a conjugate acid-base pair? Select all that apply. (A) \( \mathrm{NH}_{4}+ \) and CN - (B) \( \mathrm{NH}_{3} \) and HCN (D) \( \mathrm{NH} 4+ \) and NH 3 and HCN

45. [Application] Acid rain. One study found that the average pH value of rainfall in Utah was about 5.8 and in Pennsylvania it was about 4.4. How much more acidic was the rainfall in Pennsylvania than the rainfall in Utah?

What is the formula for the conjugate base of HI ? (A) \( \mathrm{H}_{21+} \) (B) \( 1 \cdot \) (C) \( \mathrm{HIO}+ \) (D) 10 -

Which equation properly depicts the reaction between \( \mathrm{HNO}_{3} \) and water? (A) \( \mathrm{HNO}_{3}(\mathrm{aq})+\mathrm{H} 2 \mathrm{O}(\mathrm{l}) \Leftrightarrow \mathrm{H} 3 \mathrm{NO} 4(a q) \) (B) \( \mathrm{HNO} 3(\mathrm{aq})+\mathrm{H} 2 \mathrm{O}(\mathrm{l}) \Leftrightarrow \mathrm{NO}-(\mathrm{aq})+\mathrm{H} 3 \mathrm{O}+(\mathrm{aq}) \) (C) \( \mathrm{HNO} 3(\mathrm{aq})+\mathrm{H} 3 \mathrm{O}+(\mathrm{aq}) \Leftrightarrow \mathrm{H} 2 \mathrm{NO} 3+(\mathrm{aq})+\mathrm{H} 2 \mathrm{O} \) (I) (D) \( \mathrm{HNO}_{3}(\mathrm{aq})+\mathrm{OH}-(\mathrm{aq}) \Leftrightarrow \mathrm{NO}_{3}-(\mathrm{aq})+\mathrm{H} 2 \mathrm{O} \) (l)

41. pH of human blood. The hydrogen ion concentration \( \left[\mathrm{H}^{+}\right] \)of blood is approximately \( 3.98 \times 10^{-8} \) moles per liter. Find the pH value of human blood to the nearest tenth. Is human blood acidic or basic?

Using the Bronsted-Lowry definition, classify each of the following as an acid, a base, or as amphiprotic, Prompts (1) H 2 O Select match (2) \( \mathrm{H3O}+ \) (3) \( \mathrm{OH}= \)

\( \frac { 0 } { \nabla } XCl _ { 2 } ( aq ) + \frac { 0 } { \nabla } AgNO _ { 3 } ( aq ) \rightarrow \frac { 0 } { \nabla } X ( NO _ { 3 } ) _ { 2 } ( aq ) + \frac { 0 } { \nabla } AgCl ( s ) \)

\( H _ { 3 } C _ { 6 } H _ { 5 } O _ { 7 } + \underset { NaOH } { \rightarrow } Na _ { 3 } C _ { 6 } H _ { 5 } O _ { 7 } + H _ { 2 } O \)

- \( 2 \mathrm{C}_{6} \mathrm{H}_{14}+19 \mathrm{O}_{2} \ldots \mathrm{Co}_{2}+14 \mathrm{H}_{2} \mathrm{O} \) - If I start with 38 grams of \( \mathrm{C}_{6} \mathrm{H}_{14} \) and 54 g of \( \mathrm{O}_{2} \) how many grams of water should I end up with?