Find the exact value of each of the remaining tigonometrie functions of 0 . Rationalize denominatore when applicable. \( \tan 0=\frac{4}{3} \), given that 0 is in quadrant । (Simplify your answer, including any radicals. Use integers of fractions for any numbers in the expression.) II. The function la undefined, Select the correct oholee below and, if necessary, fill in the answer box to complete your choice. A. \( \operatorname{coc} 0=\frac{5}{4} \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( \sec 0=\frac{5}{3} \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( \cot 0= \) \( \square \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined. View an example Get more help * MacBook Air
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To find the exact values of the remaining trigonometric functions given that \(\tan \theta = \frac{4}{3}\) and \(\theta\) is in Quadrant II, we can use the Pythagorean identity to find \(\sin \theta\) and \(\cos \theta\). Given \(\tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{4}{3}\), we can think of a right triangle with opposite side 4 and adjacent side 3. The hypotenuse can be calculated using the Pythagorean theorem: \[ \text{hypotenuse} = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5. \] From the triangle, we get \(\sin \theta = \frac{4}{5}\) and since \(\theta\) is in Quadrant II, \(\cos \theta = -\frac{3}{5}\). Now we can find the other trigonometric functions: 1. \(\csc 0 = \frac{1}{\sin 0} = \frac{5}{4}\) (Choice A) 2. \(\sec 0 = \frac{1}{\cos 0} = -\frac{5}{3}\) (Choice A) 3. \(\cot 0 = \frac{1}{\tan 0} = \frac{3}{4}\) (Choice A) With all values computed, now we can fill in the choices accordingly!