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\begin{tabular}{l}\hline Question 9 N II Pause Q Zoom \\ \hline \\ Solve the system. \\ \( x+y=-1 \) \\ \( 3 x-y=5 \)\end{tabular}

Ask by Byrd Elliott. in the United States
Jan 24,2025

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Answer

The solution to the system is \( x = 1 \) and \( y = -2 \).

Solution

To solve the given system of equations: \[ \begin{cases} x + y = -1 \quad \quad \quad \quad (1) \\ 3x - y = 5 \quad \quad \quad \quad (2) \end{cases} \] we can use either the **elimination method** or the **substitution method**. Here, we'll demonstrate both methods. --- ### **1. Elimination Method** **Step 1:** Add equations (1) and (2) to eliminate \( y \). \[ \begin{align*} (x + y) + (3x - y) &= -1 + 5 \\ 4x &= 4 \end{align*} \] **Step 2:** Solve for \( x \). \[ x = \frac{4}{4} = 1 \] **Step 3:** Substitute \( x = 1 \) back into equation (1) to find \( y \). \[ 1 + y = -1 \\ y = -1 - 1 \\ y = -2 \] --- ### **2. Substitution Method** **Step 1:** Solve equation (1) for \( y \). \[ y = -1 - x \] **Step 2:** Substitute \( y = -1 - x \) into equation (2). \[ 3x - (-1 - x) = 5 \\ 3x + 1 + x = 5 \\ 4x + 1 = 5 \] **Step 3:** Solve for \( x \). \[ 4x = 5 - 1 \\ 4x = 4 \\ x = \frac{4}{4} = 1 \] **Step 4:** Substitute \( x = 1 \) back into \( y = -1 - x \) to find \( y \). \[ y = -1 - 1 = -2 \] --- ### **Solution** \[ \boxed{\,x = 1,\quad y = -2\,} \]

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To solve the system of equations, we can use the substitution or elimination method. Let's use substitution for this example. From the first equation, \(x + y = -1\), we can express \(y\) as \(y = -1 - x\). Now, substitute this expression for \(y\) into the second equation: \(3x - (-1 - x) = 5\). This simplifies to: \(3x + 1 + x = 5\) \(4x + 1 = 5\) \(4x = 4\) \(x = 1\). Now plug \(x = 1\) back into the expression for \(y\): \(y = -1 - 1 = -2\). So, the solution to the system is \(x = 1\) and \(y = -2\). --- For a further twist, if you are curious, you can visualize this system geometrically! Each equation represents a line on a graph, and the point where they intersect is the solution. Thus, \( (1, -2) \) is where these two lines meet, confirming our algebraic solution! Also, watch out for common mistakes! A frequent error is misapplying signs when moving terms. Double-check your calculations, and remember that careful tracking of negative signs can save you from getting tangled up in the math!

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