86. A construction company owns a triangular lot in at a " Y " intersection. The length of the property line AB is 140 feet. The length of the property line BC is 220 feet. The angle between the property lines AB and BC is \( 125^{\circ} \). What is the area of the lot? Round to the nearest hundredth.
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To find the area of the triangular lot, we can use the formula: \[ \text{Area} = \frac{1}{2} \times AB \times BC \times \sin(\theta) \] In this case: - \( AB = 140 \) feet - \( BC = 220 \) feet - \( \theta = 125^\circ \) First, we calculate the sine of \( 125^\circ \): \[ \sin(125^\circ) \approx 0.8192 \] Now, we plug the values into the area formula: \[ \text{Area} = \frac{1}{2} \times 140 \times 220 \times 0.8192 \] Calculating this gives: \[ \text{Area} \approx \frac{1}{2} \times 140 \times 220 \times 0.8192 \approx 12,211.84 \text{ square feet} \] So, the area of the lot is approximately **12,211.84 square feet** when rounded to the nearest hundredth.