11. Matching Type: Balance the given equations in Column 1, then choose the lefter under Column 2 that corresponds to the sum of the coefficients of each balanced equation. Identi the type of chemical reaction by choosing the letter under Column 3.(15 points) Example: $$ \begin{array}{c} \text { 1-2. } 2 \mathrm{H}_{2}+\mathrm{O}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} \ 2+1+2=5 \ \text { Synthesis } \end{array} $$ Answers: 1. C (2 points) 2. A (1 point) Column 1 Column 2 20-21. $$ \mathrm{Fe}+\mathrm{Cl}_{2} \rightarrow \mathrm{FeCl}_{3} $$ A. 6 B. 7 C. 8 D. 9 22-23. $$ \mathrm{MnO}_{2}+\mathrm{HCl} \rightarrow \mathrm{MnCl}_{2}+\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O} $$ A. 6 B. 7 C. $$ 8 \quad 0.9 $$ 24-25. $$ \mathrm{Fe}_{2} \mathrm{O}_{3}+\mathrm{HCl} \rightarrow \mathrm{FeCl}_{3}+\mathrm{H}_{2} \mathrm{O} $$ A. 12 B. 13 C. 14 D. 15 26-27. $$ \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}+\mathrm{I}_{2} \rightarrow \mathrm{Nal}+\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6} $$ $$ \begin{array}{llll}\text { A. } 6 & 8.7 & \text { C. } 8 & \text { D. } 9\end{array} $$ $$ 28.29 . \mathrm{Na}+\mathrm{KNO}_{3} \rightarrow \mathrm{~K}_{2} \mathrm{O}+\mathrm{Na}_{2} \mathrm{O}+\mathrm{N}_{2} $$ A. 10 B. 16 C. 19 D. 20 Column 3 A. Synthesis B. Decomposition C. Single Replacement D. Double Replacement

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To solve the problem, we need to balance each chemical equation provided in Column 1, calculate the sum of the coefficients for each balanced equation, and then identify the type of chemical reaction. Let's go through each equation step by step.

### 20-21. $$ \mathrm{Fe} + \mathrm{Cl}_{2} \rightarrow \mathrm{FeCl}_{3} $$

1. **Balancing the equation:**
   - On the left, we have 1 Fe and 2 Cl.
   - On the right, we have 1 Fe and 3 Cl in $$ \mathrm{FeCl}_{3} $$.
   - To balance Cl, we need 3 Cl on the left, which means we need $$ \frac{3}{2} $$ $$ \mathrm{Cl}_{2} $$ or 3 Cl atoms.
   - Thus, we can multiply the entire equation by 2 to eliminate the fraction:
   $$
   2 \mathrm{Fe} + 3 \mathrm{Cl}_{2} \rightarrow 2 \mathrm{FeCl}_{3}
   $$

2. **Sum of coefficients:**
   - Coefficients: 2 (Fe) + 3 (Cl₂) + 2 (FeCl₃) = 7

3. **Type of reaction:**
   - This is a **Synthesis** reaction.

### 22-23. $$ \mathrm{MnO}_{2} + \mathrm{HCl} \rightarrow \mathrm{MnCl}_{2} + \mathrm{Cl}_{2} + \mathrm{H}_{2} \mathrm{O} $$

1. **Balancing the equation:**
   - On the left: 1 Mn, 2 O, 1 H, and 1 Cl.
   - On the right: 1 Mn, 2 Cl in $$ \mathrm{MnCl}_{2} $$, 2 Cl in $$ \mathrm{Cl}_{2} $$, and 2 H in $$ \mathrm{H}_{2}O $$.
   - We need to balance H and Cl:
   $$
   \mathrm{MnO}_{2} + 4 \mathrm{HCl} \rightarrow \mathrm{MnCl}_{2} + 2 \mathrm{Cl}_{2} + 2 \mathrm{H}_{2}O
   $$

2. **Sum of coefficients:**
   - Coefficients: 1 (MnO₂) + 4 (HCl) + 1 (MnCl₂) + 2 (Cl₂) + 2 (H₂O) = 10

3. **Type of reaction:**
   - This is a **Single Replacement** reaction.

### 24-25. $$ \mathrm{Fe}_{2} \mathrm{O}_{3} + \mathrm{HCl} \rightarrow \mathrm{FeCl}_{3} + \mathrm{H}_{2} \mathrm{O} $$

1. **Balancing the equation:**
   - On the left: 2 Fe, 3 O, 1 Cl.
   - On the right: 2 Fe in $$ \mathrm{FeCl}_{3} $$, 3 Cl, and 2 H in $$ \mathrm{H}_{2}O $$.
   - We need to balance:
   $$
   \mathrm{Fe}_{2} \mathrm{O}_{3} + 6 \mathrm{HCl} \rightarrow 2 \mathrm{FeCl}_{3} + 3 \mathrm{H}_{2}O
   $$

2. **Sum of coefficients:**
   - Coefficients: 1 (Fe₂O₃) + 6 (HCl) + 2 (FeCl₃) + 3 (H₂O) = 12

3. **Type of reaction:**
   - This is a **Double Replacement** reaction.

### 26-27. $$ \mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3} + \mathrm{I}_{2} \rightarrow \mathrm{NaI} + \mathrm{Na}_{2} \mathrm{S}_{4} \mathrm{O}_{6} $$

1. **Balancing the equation:**
   - On the left: 2 Na, 2 S, 3 O, 2 I.
   - On the right: 1 Na in $$ \mathrm{NaI} $$, 2 Na in $$ \mathrm{Na}_{2}S_{4}O_{6} $$.
   - We need to balance:
   $$
   \mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3} + \mathrm{I}_{2} \rightarrow 2 \mathrm{NaI} + \mathrm{Na}_{2} \mathrm{S}_{4} \mathrm{O}_{6}
   $$

2. **Sum of coefficients:**
   - Coefficients: 1 (Na₂S₂O₃) + 1 (I₂) + 2 (NaI) + 1 (Na₂S₄O₆) = 5

3. **Type of reaction:**
   - This is a **Single Replacement** reaction.

### 28-29. $$ \mathrm{Na} + \mathrm{KNO}_{3} \rightarrow \mathrm{K}_{2} \mathrm{O} + \mathrm{Na}_{2} \mathrm{O} + \mathrm{N}_{2} $$

1. **Balancing the equation:**
   - On the left: 1 Na, 1 K, 1 N, 3 O.
   - On the right: 2 K in $$ \mathrm{K}_{2}O $$, 2 Na in $$ \mathrm{Na}_{2}O $$, and 2 N in $$ \mathrm{N}_{2} $$.
   - We need to balance:
   $$
   4 \mathrm{Na} + 2 \mathrm{KNO}_{3} \rightarrow 2 \mathrm{K}_{2}O + 2 \mathrm{Na}_{2}O + \mathrm{N}_{2}
   $$

2. **Sum of coefficients:**
   - Coefficients: 4 (Na) + 2 (KNO₃) + 2 (K₂O) + 2 (Na₂O) + 1 (N₂) = 11

3. **Type of reaction:**
   - This is a **Double Replacement** reaction.

### Summary of Answers:
- **20-21:** 7, Synthesis
- **22-23:** 10, Single Replacement
- **24-25:** 12, Double Replacement
- **26-27:** 5, Single Replacement
- **28-29:** 11, Double Replacement

### Final Answers:
1. **20-21:** B (7), A (Synthesis)
2. **22-23:** A (10), C (Single Replacement)
3. **24-25:** A (
1. **20-21:** B (7), A (Synthesis) 2. **22-23:** A (10), C (Single Replacement) 3. **24-25:** A (12), D (Double Replacement) 4. **26-27:** A (5), C (Single Replacement) 5. **28-29:** D (11), D (Double Replacement)

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