1. \( 3(x+2)=18 \) 2. \( 2(3 y-1)=16 \) 3. \( 4 a+3-a=12 \) 4. \( 5 b-2+2 b=19 \) 5. \( -2(c+4)=6 \)

Let's solve each of the given equations step by step. --- **1. \( 3(x + 2) = 18 \)** **Solution:** \[ \begin{align*} 3(x + 2) &= 18 \\ x + 2 &= \frac{18}{3} \quad \text{(Divide both sides by 3)} \\ x + 2 &= 6 \\ x &= 6 - 2 \\ x &= 4 \end{align*} \] **Answer:** \( x = 4 \) --- **2. \( 2(3y - 1) = 16 \)** **Solution:** \[ \begin{align*} 2(3y - 1) &= 16 \\ 3y - 1 &= \frac{16}{2} \quad \text{(Divide both sides by 2)} \\ 3y - 1 &= 8 \\ 3y &= 8 + 1 \\ 3y &= 9 \\ y &= \frac{9}{3} \\ y &= 3 \end{align*} \] **Answer:** \( y = 3 \) --- **3. \( 4a + 3 - a = 12 \)** **Solution:** \[ \begin{align*} 4a + 3 - a &= 12 \\ (4a - a) + 3 &= 12 \\ 3a + 3 &= 12 \\ 3a &= 12 - 3 \\ 3a &= 9 \\ a &= \frac{9}{3} \\ a &= 3 \end{align*} \] **Answer:** \( a = 3 \) --- **4. \( 5b - 2 + 2b = 19 \)** **Solution:** \[ \begin{align*} 5b - 2 + 2b &= 19 \\ (5b + 2b) - 2 &= 19 \\ 7b - 2 &= 19 \\ 7b &= 19 + 2 \\ 7b &= 21 \\ b &= \frac{21}{7} \\ b &= 3 \end{align*} \] **Answer:** \( b = 3 \) --- **5. \( -2(c + 4) = 6 \)** **Solution:** \[ \begin{align*} -2(c + 4) &= 6 \\ c + 4 &= \frac{6}{-2} \quad \text{(Divide both sides by -2)} \\ c + 4 &= -3 \\ c &= -3 - 4 \\ c &= -7 \end{align*} \] **Answer:** \( c = -7 \) --- Feel free to reach out if you have any more questions!