Question
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Simplify, answerwrite with positive exponents: \( \frac{-8 a^{5} b^{9} c}{2 a^{3} b^{8} c^{-3}} \)

Ask by Pollard Ryan. in the United States
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ -4a^{2}bc^{4} \]

Solution

To simplify the expression \( \frac{-8 a^{5} b^{9} c}{2 a^{3} b^{8} c^{-3}} \) and write it with positive exponents, follow these steps: 1. **Simplify the coefficients:** \[ \frac{-8}{2} = -4 \] 2. **Simplify the variables by subtracting the exponents (since you're dividing):** - For \( a \): \[ a^{5} \div a^{3} = a^{5-3} = a^{2} \] - For \( b \): \[ b^{9} \div b^{8} = b^{9-8} = b^{1} = b \] - For \( c \): \[ c \div c^{-3} = c^{1-(-3)} = c^{4} \] 3. **Combine all simplified parts:** \[ -4 \cdot a^{2} \cdot b \cdot c^{4} = -4a^2bc^4 \] **Final Answer:** \[ -4a^{2}bc^{4} \]

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The Deep Dive

To simplify \( \frac{-8 a^{5} b^{9} c}{2 a^{3} b^{8} c^{-3}} \), start by dividing the coefficients and applying the properties of exponents. 1. Divide the coefficients: \( \frac{-8}{2} = -4 \). 2. For \( a^{5} \div a^{3} \), use the rule \( a^{m} \div a^{n} = a^{m-n} \): \[ a^{5-3} = a^{2}. \] 3. For \( b^{9} \div b^{8} \): \[ b^{9-8} = b^{1} = b. \] 4. For \( c \div c^{-3} \), remember that dividing by a negative exponent is the same as multiplying by the positive exponent: \[ c \div c^{-3} = c^{1 - (-3)} = c^{4}. \] Putting it all together: \[ -4 a^{2} b c^{4}. \] Thus, the simplified expression with positive exponents is: \[ \boxed{-4 a^{2} b c^{4}}. \]

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