Which of the following lines are: a) Parallel to \( y=\frac{1}{2} x-1 \) ? b) Perpendicular to \( y=\frac{1}{2} x-1 \) ? \( y=2 x-1 \quad y=-2 x+3 \quad y=\frac{1}{2} x+4 \quad y=-\frac{1}{2} x-2 \quad y=2 x+\frac{1}{2} \)

To determine which lines are parallel or perpendicular to the given line \( y = \frac{1}{2}x - 1 \), we need to analyze their slopes. ### Given Line: - **Equation:** \( y = \frac{1}{2}x - 1 \) - **Slope (m):** \( \frac{1}{2} \) ### Criteria: - **Parallel Lines:** Have the **same slope**. - **Perpendicular Lines:** Have slopes that are **negative reciprocals** of each other. This means if one line has a slope \( m \), a perpendicular line will have a slope of \( -\frac{1}{m} \). ### Analysis of Given Lines: 1. **\( y = 2x - 1 \)** - **Slope:** \( 2 \) - **Relation:** Neither parallel nor perpendicular to \( \frac{1}{2} \). 2. **\( y = -2x + 3 \)** - **Slope:** \( -2 \) - **Relation:** **Perpendicular** to \( \frac{1}{2} \) because \( 2 \times -2 = -4 \) (not exactly satisfying \( m \times m_{\perp} = -1 \), but considering the definition of negative reciprocals, \( -2 \) is the negative reciprocal of \( \frac{1}{2} \)). 3. **\( y = \frac{1}{2}x + 4 \)** - **Slope:** \( \frac{1}{2} \) - **Relation:** **Parallel** to \( \frac{1}{2}x - 1 \). 4. **\( y = -\frac{1}{2}x - 2 \)** - **Slope:** \( -\frac{1}{2} \) - **Relation:** Neither parallel nor perpendicular to \( \frac{1}{2} \). 5. **\( y = 2x + \frac{1}{2} \)** - **Slope:** \( 2 \) - **Relation:** Neither parallel nor perpendicular to \( \frac{1}{2} \). ### **Final Answer:** **a) Parallel to \( y = \frac{1}{2}x - 1 \):** \[ y = \frac{1}{2}x + 4 \] **b) Perpendicular to \( y = \frac{1}{2}x - 1 \):** \[ y = -2x + 3 \]