\begin{tabular}{l} I. Convert each improper fraction to a whole or mixed number. \\ \( \frac{15}{2}= \) \\ \( \frac{35}{4}= \) \\ \( \frac{124}{12}= \) \\ \hline\( \frac{52}{13} \)\end{tabular}\( = \)

To convert each improper fraction to a whole or mixed number, we will follow these steps: 1. Divide the numerator by the denominator. 2. The quotient will be the whole number part. 3. The remainder will be the new numerator for the fractional part. 4. The denominator remains the same. Let's solve each fraction step by step. ### 1. Convert \( \frac{15}{2} \) - Divide \( 15 \) by \( 2 \): \[ 15 \div 2 = 7 \quad \text{(whole number part)} \] Remainder: \[ 15 - (2 \times 7) = 1 \quad \text{(remainder)} \] - So, \( \frac{15}{2} = 7 \frac{1}{2} \). ### 2. Convert \( \frac{35}{4} \) - Divide \( 35 \) by \( 4 \): \[ 35 \div 4 = 8 \quad \text{(whole number part)} \] Remainder: \[ 35 - (4 \times 8) = 3 \quad \text{(remainder)} \] - So, \( \frac{35}{4} = 8 \frac{3}{4} \). ### 3. Convert \( \frac{124}{12} \) - Divide \( 124 \) by \( 12 \): \[ 124 \div 12 = 10 \quad \text{(whole number part)} \] Remainder: \[ 124 - (12 \times 10) = 4 \quad \text{(remainder)} \] - So, \( \frac{124}{12} = 10 \frac{4}{12} \). - We can simplify \( \frac{4}{12} \) to \( \frac{1}{3} \), so: \[ \frac{124}{12} = 10 \frac{1}{3}. \] ### 4. Convert \( \frac{52}{13} \) - Divide \( 52 \) by \( 13 \): \[ 52 \div 13 = 4 \quad \text{(whole number part)} \] Remainder: \[ 52 - (13 \times 4) = 0 \quad \text{(remainder)} \] - So, \( \frac{52}{13} = 4 \). ### Summary of Results - \( \frac{15}{2} = 7 \frac{1}{2} \) - \( \frac{35}{4} = 8 \frac{3}{4} \) - \( \frac{124}{12} = 10 \frac{1}{3} \) - \( \frac{52}{13} = 4 \) Thus, the final answers are: - \( \frac{15}{2} = 7 \frac{1}{2} \) - \( \frac{35}{4} = 8 \frac{3}{4} \) - \( \frac{124}{12} = 10 \frac{1}{3} \) - \( \frac{52}{13} = 4 \)