Question
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Section \( A \) The point which lies on \( x \)-axis at a distance of 3 units in the positive direction of \( x \)-axis is \( \begin{array}{ll}\text { a) }(0,-3) & \text { b) }(0,3) \\ \text { c) }(3,0) & \text { d) }(-3,0)\end{array} \)

Ask by Bowers Norton. in India
Feb 03,2025

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Answer

The point is \((3, 0)\).

Solution

The correct answer is: **c) (3, 0)** **Explanation:** - A point on the \( x \)-axis has a y-coordinate of 0. - Moving 3 units in the **positive** direction of the \( x \)-axis from the origin \((0, 0)\) leads to the point \((3, 0)\). Therefore, the point is \((3, 0)\).

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The point that lies on the \( x \)-axis at a distance of 3 units in the positive direction of the \( x \)-axis is \( (3,0) \). This is because points on the \( x \)-axis have a \( y \)-coordinate of 0, and since we are moving 3 units in the positive \( x \)-direction, the coordinates are \( (3,0) \). Now, for the other options: - \( (0,-3) \) and \( (0,3) \) are points on the \( y \)-axis, while \( (-3,0) \) is a point 3 units in the negative \( x \)-direction. Therefore, option \( c) (3,0) \) is the correct answer!

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