Question

TRY IT YOURSELF (a) The masses of 2 bags of sugar, \( A \) and \( B \), are 750 g and \( 1 \frac{1}{3} \mathrm{~kg} \) respectively. Find the ratio of the mass of \( B \) to the mass of \( A \).

Ask by Tyler Reed. in Indonesia
Jan 23,2025

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Tutor-Verified Answer

Answer

The ratio of the mass of bag \( B \) to bag \( A \) is **16:9**.

Solution

To find the ratio of the mass of bag \( B \) to the mass of bag \( A \), follow these steps: 1. **Convert Units to the Same Measure:** - **Mass of Bag \( A \):** \( 750 \) grams (already in grams). - **Mass of Bag \( B \):** \( 1 \frac{1}{3} \) kilograms. Convert kilograms to grams: \[ 1 \, \text{kg} = 1000 \, \text{grams} \] \[ 1 \frac{1}{3} \, \text{kg} = \frac{4}{3} \, \text{kg} = \frac{4}{3} \times 1000 \, \text{grams} = 1333.\overline{3} \, \text{grams} \] 2. **Set Up the Ratio:** The ratio of the mass of \( B \) to \( A \) is: \[ \text{Mass of } B : \text{Mass of } A = 1333.\overline{3} \, \text{g} : 750 \, \text{g} \] 3. **Simplify the Ratio:** To simplify the ratio, it's easier to eliminate the decimal by multiplying both terms by 3: \[ 1333.\overline{3} \times 3 = 4000 \, \text{g} \] \[ 750 \times 3 = 2250 \, \text{g} \] Now, the ratio is: \[ 4000 : 2250 \] Divide both numbers by their greatest common divisor (which is 250): \[ \frac{4000}{250} : \frac{2250}{250} = 16 : 9 \] 4. **Final Answer:** The ratio of the mass of \( B \) to the mass of \( A \) is **16:9**. **Answer:** After simplifying, the ratio of mass B to mass A is 16 to 9.

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To find the ratio of the mass of bag \( B \) to the mass of bag \( A \), we first need to convert the mass of bag \( B \) into the same unit as bag \( A \). The mass of bag \( A \) is 750 g. The mass of bag \( B \) is \( 1 \frac{1}{3} \, \text{kg} \). Converting this into grams: \( 1 \frac{1}{3} \, \text{kg} = \frac{4}{3} \, \text{kg} = \frac{4}{3} \times 1000 \, \text{g} = \frac{4000}{3} \, \text{g} \approx 1333.33 \, \text{g} \). Now, set up the ratio: \(\text{Ratio of } B \text{ to } A = \frac{1333.33 \, \text{g}}{750 \, \text{g}} \). This simplifies to: \(\frac{1333.33}{750} \approx \frac{4000/3}{750} = \frac{4000}{2250} = \frac{16}{9}\). Thus, the ratio of the mass of \( B \) to the mass of \( A \) is \( \frac{16}{9} \).

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