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\( 912 m ^ { 2 } - 19 m n + 5 n ^ { 2 } \)

Ask by Mccarthy Watkins. in South Africa
Feb 03,2025

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Answer

The expression \( 912m^2 - 19mn + 5n^2 \) cannot be factored into simpler binomial terms with integer coefficients. It is **irreducible** over the integers.

Solution

The expression you've provided is a quadratic in terms of variables \( m \) and \( n \): \[ 912m^2 - 19mn + 5n^2 \] ### **Objective: Factor the Expression** To factor this quadratic expression, we look for two binomials of the form: \[ (am + bn)(cm + dn) \] When expanded, this yields: \[ ac\,m^2 + (ad + bc)\,mn + bd\,n^2 \] By comparing coefficients, we establish the following system of equations: 1. \( ac = 912 \)          *(Coefficient of \( m^2 \))* 2. \( ad + bc = -19 \)      *(Coefficient of \( mn \))* 3. \( bd = 5 \)           *(Coefficient of \( n^2 \))* #### **Step 1: Find Possible Pairs for \( a \) and \( c \)** First, factorize 912: \[ 912 = 2^4 \times 3 \times 19 \] Possible integer pairs \((a, c)\) such that \( ac = 912 \): - \( (1, 912) \) - \( (2, 456) \) - \( (3, 304) \) - \( (4, 228) \) - \( (6, 152) \) - \( (8, 114) \) - \( (12, 76) \) - \( (16, 57) \) - \( (19, 48) \) - \( (24, 38) \) - ...and their negative counterparts. #### **Step 2: Find Possible Pairs for \( b \) and \( d \)** Since \( bd = 5 \) and 5 is a prime number, the possible integer pairs are: - \( (1, 5) \) - \( (-1, -5) \) #### **Step 3: Check for Compatibility** For each combination of \((a, c)\) and \((b, d)\), check if \( ad + bc = -19 \). **Example Attempt:** Let's try \( b = 1 \) and \( d = 5 \): 1. \( ad + bc = a \times 5 + c \times 1 = 5a + c = -19 \) 2. From \( ac = 912 \), suppose \( a = 19 \), then \( c = 48 \). 3. Check \( 5a + c = 5 \times 19 + 48 = 95 + 48 = 143 \neq -19 \) This doesn't satisfy the second equation. Repeating this process for all possible pairs reveals that **no integer solutions satisfy all three equations simultaneously**. ### **Conclusion** The quadratic expression: \[ 912m^2 - 19mn + 5n^2 \] **is not factorable** into binomials with integer coefficients. This means the expression is **irreducible** over the set of integers. ### **Alternative Approach: Using the Quadratic Formula** If you consider the expression as a quadratic in \( m \), you can explore its roots using the quadratic formula: \[ m = \frac{19n \pm \sqrt{(19n)^2 - 4 \times 912 \times 5n^2}}{2 \times 912} = \frac{19n \pm \sqrt{-17879n^2}}{1824} \] The discriminant here is negative (\( -17879n^2 \)), indicating that the quadratic does not have real roots. This further confirms that the expression cannot be factored into real linear factors. ### **Final Answer** The expression \( 912m^2 - 19mn + 5n^2 \) cannot be factored into simpler binomial terms with integer coefficients. It is **irreducible** over the integers.

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This expression looks like a quadratic in the form of \( ax^2 + bxy + cy^2 \). To factor it, we should look for two numbers that multiply to \( ac \) (the product of the coefficient of \( m^2 \) and the coefficient of \( n^2 \), which is \( 912 \times 5 = 4560 \)) and add to \( b \) (the coefficient of \( mn \), which is \( -19 \)). After finding those numbers, we can use them to express the quadratic as a product of two binomials. You might be wondering how to connect this to real life. Quadratics can model many scenarios, like projectile motion or optimizing areas. For example, if you're building a garden with a specific area and need to express dimensions in terms of \( m \) and \( n \), efficiently solving quadratic equations can save you time and materials, making your project come to life!

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