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Inctions \[ f(x)=\sqrt{2 x-18} \] Find the domain of the function. The domain is \( \square \). (Type your answer in interval notation.)

Ask by Coleman Williams. in the United States
Jan 23,2025

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Answer

The domain is \([9, \infty)\).

Solution

To find the domain of the function \( f(x) = \sqrt{2x - 18} \), we need to ensure that the expression inside the square root is non-negative (since the square root of a negative number is not defined in the set of real numbers). 1. **Set the inside of the square root greater than or equal to zero:** \[ 2x - 18 \geq 0 \] 2. **Solve for \( x \):** \[ 2x \geq 18 \] \[ x \geq 9 \] Therefore, the domain of the function is all real numbers \( x \) such that \( x \) is greater than or equal to 9. **The domain is** \([9, \infty)\). **Answer:** \([9, \infty)\)

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The Deep Dive

To find the domain of the function \( f(x)=\sqrt{2x-18} \), we need to ensure that the expression inside the square root is non-negative. So, we set up the inequality: \[ 2x - 18 \geq 0 \] Solving for \( x \): \[ 2x \geq 18 \] \[ x \geq 9 \] Thus, the domain of \( f(x) \) is \( [9, \infty) \). The domain is \( [9, \infty) \).

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