Question
Inctions \[ f(x)=\sqrt{2 x-18} \] Find the domain of the function. The domain is \( \square \). (Type your answer in interval notation.)
Ask by Coleman Williams. in the United States
Jan 23,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The domain is \([9, \infty)\).
Solution
To find the domain of the function \( f(x) = \sqrt{2x - 18} \), we need to ensure that the expression inside the square root is non-negative (since the square root of a negative number is not defined in the set of real numbers).
1. **Set the inside of the square root greater than or equal to zero:**
\[
2x - 18 \geq 0
\]
2. **Solve for \( x \):**
\[
2x \geq 18
\]
\[
x \geq 9
\]
Therefore, the domain of the function is all real numbers \( x \) such that \( x \) is greater than or equal to 9.
**The domain is** \([9, \infty)\).
**Answer:** \([9, \infty)\)
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The Deep Dive
To find the domain of the function \( f(x)=\sqrt{2x-18} \), we need to ensure that the expression inside the square root is non-negative. So, we set up the inequality: \[ 2x - 18 \geq 0 \] Solving for \( x \): \[ 2x \geq 18 \] \[ x \geq 9 \] Thus, the domain of \( f(x) \) is \( [9, \infty) \). The domain is \( [9, \infty) \).